C++
请在下面程序的横线处填上适当字句,以使程序完整,并使程序的输出为8。
#include<iostream.h>
template<class T>
void fun(___________(1)___________)
{
t=x[0];
for(int i=0;i<n;i++)
if(a[i]>t)
t=a[i];
}
void main()
{
int a[]={3,5,8,4,6};
int m;
fun(a,5,__(2)____);
cout<<m<<endl;
}下面程序通过把类Distance声明为类Point的友元类来实现计算两点之间的距离。请在下面程序的横线处填上适当字句,以使程序完整。
#include<iostream>
#include<cmath>
using namespace std;
class Point
{
double X,Y;
public:
Point(double x,double y)
{X=x;Y=y;}
____________(1)____________;
};
class Distance
{
public:
double Dis(Point& p1,Point& p2);
{
double t;
____________________(2)___________________;
return t;
}
}
void main()
{
Point p(10,10),q(20,20);
Distance d;
cout<<d.Dis(p,q)<<endl;
}程序阅读题
1、
#include <iostream>
using namespace std;
int& element(int x[],int index)
{
return x[index+1];
}
void main()
{
int a[]={3,7,2,1,5};
element(a,3)=9;
for(int i=0;i<5;i++)
cout<<a[i]<<’’;
}2、
#include<iostream>
using namespace std;
class A
{
int num;
public:
A()
{
num=0;cout<<"A default constructor"<<endl;}
A(int n)
{num=n;cout<<”A constructor,num=”<<num<<endl;}
~A()
{cout<<"A destructor,num="<<num<<endl;}
};
void main()
{
A a,*p;
p=new A(2);
a=*p;
delete p;
cout<<”Exiting main”<<endl;
}3、
#include<iostream>
using namespace std;
class Format
{
public:
virtual void header()
{cout<<"This is a head"<<endl;
}virtual void footer()
{cout<<"This is a footer"<<endl;}
virtual void body()
{cout<<"This is a body"<<endl;}
void display()
{header();body();footer();}
};
class MyFormat:public Format
{
public:
void header()
{cout<<"This is my header"<<endl;}
void footer()
{cout<<"This is my footer"<<endl;}
};
void main()
{
Format * p;
p=new Format;
p->display();
delete p;
p=new MyFormat;
p->display();
delete p;
}4、从键盘输入8 4 3 1 9 6 1 1 2 5,给出程序的输出结果。
#include<iostream>
#include<vector>
#include<stack>
#include<iterator>
using namespace std;
main()
{
vector<int> v;
stack<int> s;
int i,n,x;
cin>>n;
for(i=0;i<n;i++)
{
cin>>x;
v.push_back(x);
}
for(vector<int>::iterator p=v.begin();p!=v.end();p++)
if(*p%2==0)
s.push(*p);
while(!s.empty())
{
cout<<s.top()<<endl;
s.pop();
}
}5、
#include<iostream>
#include<exception>
using namespace std;
class Fract
{
int den,num;
public:
Fract(int d=0,int n=1)
{
if(n==0)
throw exception("divided by zero");
den = d;num=n;
}
int& operator[](int index)
{
if(index<0||index>1)
throw exception("index out of range");
if(index==0)
return den;
if(index==1)return num;
}
void show()
{ cout<<den<<"/"<<num<<endl;}
};
void main()
{
try
{
Fract f(0,2);
f.show();
cout<<f[1]<<"/"<<f[2]<<endl;
}
catch(exception e)
{
cout<<e.what()<<endl;
}
}请在下面程序的横线处填上适当内容,以使程序完整,并使运行结果为:Hello
hELLO
#include <iostream.h>
#include <string.h>
class Words
{char *str;
public:
Words(char *s)
{str=new char[strlen(s)+1];
strcpy(str,s);
}
void disp(){cout<<str<<endl;}
char operator[](int i)
{if(str[i]>='A'&&str[i]<='Z')
return char(str[i]+32);
else if(str[i]>='a'&&str[i]<='z')
return char(str[i]-32);
else
return str[i];
}
};
int main()
{int i;char *s="Hello";
Words word(s);
______________(1)____________;
for (i=0;i<strlen(s);i++)
______________(2)____________;
cout<<endl;
}利用函数模板,设计求一个数组元素之和的函数sum和两个数组元素之和的函数sum,请在下面程序的横线处填上适当内容,以使程序完整,并使程序的输出为:
数组a之和:15
数组b之和:55
两数组之和:70
#include <iostream.h>
template <class T>
T sum (T a[],int n)
{int i;
T s=0;
for(i=0;i<n;i++)
s+=a[i];
return s;
}
template <class T>
T sum(______________(1)____________)
{
return ______________(2)____________;
}
int main()
{int a[5]={1,2,3,4,5};
int b[10]={1,2,3,4,5,6,7,8,9,10};
int s1=sum(a,5);
int s2=sum(b,10);
int s3=sum(a,5,b,10);
cout<<"数组a之和:"<<s1<<endl;
cout<<"数组b之和:"<<s2<<endl;
cout<<"两数组之和:"<<s3<<endl;
}请在下面程序的横线处填上适当字句,以使程序完整,并使程序的输出为
(1,2)
5,6
(6,9)
#include <iostream.h>
class A
{
public:
A(int i,int j){a=i;b=j;}
void move(int x,int y){ ____(1)______;b+=y;}
void show(){cout<<"("<<a<<","<<b<<")"<<endl;}
private:
int a,b;
};
class B:private A
{
public:
B(int i,int j,int k,int l):A(i,j){x=k;y=l;}
void show(){cout<<x<<","<<y<<endl;}
void fun(){move(3,5);}
void fl(){____(2)______;}
private:int x,y;
};
int main()
{A e(1,2);
e.show();
B d(3,4,5,6);
d.fun();
d.show();
d.fl();
}请在下面程序的横线处填上适当内容,以使程序完整,并使程序的输出为:
10+10i
#include <iostream.h>
class complex
{
int x,y;
public:complex(){}
complex(int i,int j)
{x=i; y=j;}
complex operator+(complex &p)
{________(1)_______;}
void show()
{cout<<x<<"+"<<y<<"i";}
};
int main()
{complex p1(5,8),p2(5,2),p3;
________(2)_______;
p3.show();程序阅读题
1、
#include <iostream.h>
class B
{
public:
B(){}
B(int i,int j){a=i;b=j;}
void printb()
{cout<<"a="<<a<<",b="<<b<<endl;}
private:
int a,b;
};
class A
{
B c;
public:
A(){}
A(int i,int j):c(i,j){}
void printa(){c.printb();}
};
int main()
{A a(7,8);
a.printa();
}2、
#include <iostream.h>
class CArray
{int *m_pArray;
int m_iSize;
public:
CArray(int iArray[],int iSize)
{m_pArray=iArray;
m_iSize=iSize;
}
int GetSize()
{return m_iSize;}
int &operator[](int i)
{return m_pArray[i];}
};
int main()
{int s[]={3,7,2,1,5};
CArray oArray(s,5);
oArray[0]=9;
for(int i=0;i<5;i++)
cout<<oArray[i]<<" ";
cout<<endl;
}3、
#include <iostream.h>
#include <math.h>
template <class T>
class TAdd
{T x,y;
public:
TAdd(T a,T b){x=a,y=b;}
T add(){return x+y;}
};
int main()
{TAdd<int> A(5,6);
TAdd<double> B(2.4,5.8);
cout<<"s1="<<A.add()<<endl;
cout<<"s2="<<B.add()<<endl;
}4、
#include <iostream.h>
class base
{
public:
void who(){cout<<"base class"<<endl;}
};
class derive1:public base
{
public:
void who(){cout<<"derive1 class"<<endl;}
};
class derive2:public base
{
public:
void who(){cout<<"derive2 class"<<endl;}
};
int main()
{base obj1,*p;
derive1 obj2;
derive2 obj3;
p=&obj1;
p->who();
p=&obj2;
p->who();
p=&obj3;
p->who();
obj2.who();
obj3.who();
}5、
#include <iostream>
#include <cmath>
#include <stdexcept>
using namespace std;
double area(double a, double b, double c) {
if (a <= 0 || b <= 0 || c <= 0)
throw invalid_argument("the side length should be positive");
if (a + b <= c || b + c <= a || c + a <= b)
throw invalid_argument("the side length should fit the triangle inequality");
double s = (a + b + c) / 2;
return sqrt(s * (s - a) * (s - b) * (s - c));
}
int main() {
double a, b, c;cin >> a >> b >> c; //输入1 2 4
try {
double s = area(a, b, c);
cout << "Area: " << s << endl;
} catch (exception &e) {
cout << "Error: " << e.what() << endl;
}
}有如下程序:
#include <iostream>
using namespace std;
class GA{
public:
virtual int f(){return 1;}
};
class GB: public GA{
public:
virtual int f(){return 2;}
};
void show(GA g){cout<<g.f();}
void display(GA &g){cout<<g.f();}
int main(){
GA a; show(a); display(a);
GB b; show(b); display(b);
Return 0;
}运行时的输出结果是( )。
下列语句分别是不同程序中的第一个输入输出语句,若去掉其中的“<
有如下定义:
int a[5]= 1,3,5,7,9),* p=a;
下列表达式中不能得到数值5的是( )。
已知类Array的定义如下:
class Array {
public :
int data[ 2 ];
Array( int n = 0 ) {
int start ;
if ( n <= 1 ) start = n - 1; else start = n;
data[ 0 ] = start ;
data[ 1 ] = start + 1 ;
}
};且有如下程序段:
Array arr(2); cout<<arr.data[0]<<arr.data[1];
则执行这个程序段的输出是( )。
已知类Time的定义如下:
class Time { //时间类
private:
int hour , minute , second ;//时、分、秒
public :
Time ( int h , int m , int s ) : hour( h ), minute( m ), second( s ) { }
____________{
switch ( index ) {
case 0 :
return hour;
case 1:
return minute;
default:
return second;
}
}
};其中横线处应为下标访问运算符[]的重载函数的函数头,横线处应填入 的代码是( )。
类Base及其派生类Derived的定义如下:
class Base {
private :
int a ;
public :
int b ;
friend class Derived ;
} ;
class Derived : public Base {
public :
void foo( ) {
a = 0;//①
b = 0;//②
}
} ;则下列说法正确的是( )。
已知类Base、Middle和Derived的定义如下:
class Base {
public :
virtual void foo ( ) { cout << 'a'; }
} ;
class Middle : public Base {
public :
void foo ( ) { cout << 'b'; }
} ;
class Derived : public Middle {
public :
void foo ( ) { cout << 'c'; }
} ;且有如下程序段:
Base * p1; Middle * p2; Derived d; p1 = &d; p1 -> foo( ); p2 = &d; p2 -> foo( );
运行这个程序段的输出是( )。
已知类AA和BB的定义如下:
class AA
{
public:
AA(){cout<<'0';}
~AA(){cout<<'1';}
};
class BB:public AA
{
public:
BB(){cout<<'2';}
~BB(){cout<<'3';}
};且有如下主函数定义:
int main(){
BB b;
return 0;
}运行这个main函数的输出是( )。
已知类CC和函数test的定义如下:
class CC {
public :
CC( ) { cout << '1'; }
~CC( ) { cout << '0'; }
};
void test ( CC c ) { cout << '2'; }且有如下main函数:
int main(){
CC c;
test(c);
return 0;
}运行这个main函数的输出是( )。
已知类Test的定义如下:
class Test{
private :
static int num ;
public :
void print ( int num ) {
cout << ++ num ;
cout << ++ this -> num;
}
};
int Test::num=0;且有如下程序段:
int main(){
Test t1,t2;
t1.print(0);
t2.print(1);
return 0;
}运行这个程序段的输出是( )。
已知类MyClass的定义如下:
class MyClass {
private :
int num ;
public :
MyClass ( int d ) : num ( d ) { }
MyClass ( const MyClass& original ) : num ( original . num ) { }
friend void print ( MyClass c ) { cout << c.num }
} ;且有如下程序段:
MyClass c(5) ; MyClass *p1; p1=&c; print(*p1) ; print(c) ;
运行这个程序段的过程中,对类MyClass的复制构造函数的调用次数是 ( )。
有如下输出语句:
cout<<setw(5)<<fixed<<setprecigion(3)<<3.1415926;
此语句的输出结果是( )。